The mass and diameter of a planet are tw...

The mass and diameter of a planet are twice those of earth. What will be the period of oscillation of a pendulum on this plenet. If it is a 2 second's pendulum on earth?

`(1)/(sqrt2)s`

`2sqrt2` s

`1/2` s

Text Solution

Verified by Experts

The correct Answer is:

`g.=(G(2M))/((2R)^2)=g/2`
`T.=2pisqrt(l/g)=sqrt2T` [For 2nd pendulum T=2 sec.]
Time period `=2sqrt2s`

Topper's Solved these Questions

GRAVITATION
ERRORLESS|Exercise Assertion and Reason |25 Videos
GRAVITATION
ERRORLESS|Exercise NCERT BASED QUESTIONS (Kepler’s Laws of Planetary Motion)|27 Videos
FRICTION
ERRORLESS|Exercise ASSERTION & REASON |8 Videos
KINETIC THEORY OF GASES
ERRORLESS|Exercise ASSERTION AND REASON |16 Videos

Similar Questions

Explore conceptually related problems

The mass and diameter of a planet are twice those of earth. What will be the period of oscillation of a pendulum on this plenet. If is a second's pendulum on earth?

The diameter of a planet is four times that of the earth. Find the time period of a pendulum on the planet, if it is a second pendulum on the earth. Take the mean density of the planet equal to that of the earth,

The mass and the diameter of a planet are three times the repective value for the Earth. The period of oscillation of a simple pendulum on the Earth is 2 s. The period of oscillation of the same pendulum on the planet would be:

What is the time period of second's pendulum ?

In a simple pendulum the period of oscillation (T) is related to the length of the pendulum (L) as

A pendulum is suspended in a lit and its period of oscillation is T_(0) when the lift is stationary. (i) What will be the period T of oscillation of pendulum, if the lift begins to accelerates downwards with an acceleration equal to (3g)/(4) ? (ii) What must be the accleration of the lift for the period of oscillation of the pendulum to be (T_(0))/(2) ?

What is time period of a second's pendulum at the centre of the earth?

ERRORLESS-GRAVITATION-Past Years Questions

A body of mass m is taken from the earth's surface to the height equal...
Text Solution
|
Two bodies of mass m(1) and m(2) are initially at rest placed infinite...
Text Solution
|
A particle of mass m is thrown upwards from the surface of the earth, ...
Text Solution
|
The velocity with which a projectile must be fired so that is escapes ...
Text Solution
|
Escape velocity on the surface of earth is 11.2 km/s . Escape velocit...
Text Solution
|
The ratio of escape velocity at earth (v(e)) to the escape velocity at...
Text Solution
|
A satellite of mass m is orbiting the earth (of radius R) at a height ...
Text Solution
|
The kinetic energies of a planet in an elliptical orbit about the Sun,...
Text Solution
|
The work done to raise a mass m from the surface of the earth to a hei...
Text Solution
|
The gravitational force between two objects is proportional to 1//R (a...
Text Solution
|
A satellite S is moving in an elliptical orbit around the earth. The m...
Text Solution
|
The mass and diameter of a planet are twice those of earth. What will ...
Text Solution
|
Potential energy of a satellite having mass ‘m’ and rotating at a heig...
Text Solution
|
An asteroid of mass m is approaching earth, initially at a distance 10...
Text Solution
|
Kepler's third law states that square of period revolution (T) of a pl...
Text Solution
|
The condition for a uniform spherical mass m of a radius r to be a bla...
Text Solution
|
A body weighs 72 N on the surface of the earth. What is the gravitatio...
Text Solution
|
A particle is released from height S from the surface of the earth. At...
Text Solution
|
The escape velocity from the earth's surface is v. The escape velocity...
Text Solution
|
A particle of mass 'm' is projected with a velocity v = k Ve (k <1) f...
Text Solution
|