A cylinder contained 10kgof gas at press...

A cylinder contained `10kg`of gas at pressure `10^(7) N / m^(2)`. The quantity of gas taken out of cylinder if final pressure is `2.5 xx 10^(6) N//m^(2)` is (Assume temperature of gas is constant)

15.2 kg

3.7 kg

Zero

7.5 kg

Text Solution

Verified by Experts

The correct Answer is:

`PV=m/MRTrArrP propm`
`rArrm_1/m_2=P_1/P_2rArr(10)/m_2=(10^7)/(2.5xx10^6)`
`rArrm_2=2.5" kg"`
Mass of gas taken out of the cylinder
`=10-2.5=7.5kg`

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