Two different masses `m` and `3 m` of an ideal gas are heated separately in a vessel of constant volume, the pressure `P` and absolute temperature `T`, graphs for these two cases are shown in the figure as `A` and `B`. The ratio of slopes of curves `B` to `A` is

Options

A. `3:1`
B. `1:3`
C. `9:1`
D. `1:9`

Answer

A

Explanation

`PV=m/MRT`
For graph A, `PV=m/MRT`
Slope of graph A,
`(P/T)=m/MR/V`
Slope of graph B,
`(P/T)=(3m)/MR/V`
`"Slope of curve B"/"Slope of curve A"=((3m)/MR/V)/(m/MR/V)=3/1`