The equation of state of gas is given `(P + (aT^(2))/(V))V^( c) = (RT + b)` where `a, b, c` and `R` are constant. The isotherms can be represented by `P = AV^(m) - BV^(n)`, where `A` and `B` depend only on temperature and

Options

A. `m=-c and n=-1`
B. `m=c and n=1`
C. `m=-c and n=1`
D. `m=c and n=-1`

Answer

A

Explanation

`(P+(aT^2)/V)V^C=(RT+b)rArrP=(RT+b)V^(-C)-(aT^2)V^(-1)`
Now, `P=AV^m-BV^n`
`m=-c and n=-1`