The average distance between molecules of an ideal gas at STP is approximately of the order of

Options

A. 1 nm
B. 100 nm
C. 100 cm
D. 1m

Answer

A

Explanation

`n=(PV)/(RT)=(10^5 xx 1)/((25)/(3)xx300)=40 implies N = 40 xx 6.023 xx 10^(23)=24 xx 10^(24)`
Average distance = `(1/N)^(1//3)=1nm`