If pressure of `CO_(2)` (real gas ) in a container is given by `P = (RT)/(2V - b) - (a)/(4b^(2))`, then mass of the gas in container is

Options

A. 11 g
B. 22 g
C. 33 g
D. 44 g

Answer

B

Explanation

Vander Waal’s equation
`(P + (n^2a)/(V^2)) (V - nb ) = nRT`
`rArr P = ((nRT)/(V - nb)- (n^2a)/V^2)…(i)`
Now, Given
`P = ((RT)/(2V - b) - a/(4b^2))…(ii)`
From (i) and (ii), n = 1/2
`rArr n = m/M rArr m = 1/2 xx 44 = 22 g`