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The volume (V) of a monatomic gas varies...

The volume `(V)` of a monatomic gas varies with its temperature `(T)` as shown in the graph. The ratio of work done by the gas, to the heat absorbed by it, when it undergoes a change from state `A` to state `B`,is

A

`2/5`

B

`2/3`

C

`1/3`

D

`2/7`

Text Solution

Verified by Experts

The correct Answer is:
A
`V prop T`
Isobaric process
`W = P DeltaV = mu R DeltaT`
`DeltaQ = mu C_P DeltaT`
For mono atomic gas `f = 3`
`C_P = (f/2 R + R) = 5/2 R`
So, `W/(DeltaQ) = (mu R DeltaT)/(mu C_P DeltaT) = 2/5`
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