`62.5 xx 10^(18)` electrons per second are flowing through a wire of area of cross-section `0.1m^(2)`, the value of current flowing wil be

Options

A. 1A
B. 0.1 A
C. `10 A`
D. 0.11 A

Answer

C

Explanation

`I = q/t = (62.5 xx 10^(18) xx 1.6 xx 10^(-19))/1 = 10 A`