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Two identical conductors maintained at s...

Two identical conductors maintained at same temperatures are given potential differences in the ratio 1:2. Then the ratio of their drift velocities is-

A

`1:2`

B

`3:2`

C

`1:1`

D

`1:2^(1//2)`

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To solve the problem, we need to find the ratio of the drift velocities of two identical conductors given that they have potential differences in the ratio of 1:2. ### Step-by-Step Solution: 1. **Understanding the Given Information**: - We have two identical conductors maintained at the same temperature. - The potential differences across them are in the ratio \( V_1 : V_2 = 1 : 2 \). - This implies that \( V_1 = k \) and \( V_2 = 2k \) for some constant \( k \). **Hint**: Identify the variables and their relationships based on the problem statement. 2. **Using the Formula for Current**: - The current \( I \) in a conductor can be expressed using the formula: \[ I = n \cdot A \cdot e \cdot v_d \] where: - \( n \) = number of charge carriers per unit volume, - \( A \) = cross-sectional area, - \( e \) = charge of an electron, - \( v_d \) = drift velocity. **Hint**: Recall the formula for current and the variables involved. 3. **Relating Current and Potential Difference**: - According to Ohm's Law, the current can also be expressed as: \[ I = \frac{V}{R} \] - For identical conductors, the resistance \( R \) is the same for both conductors, so we can express the currents for both conductors as: \[ I_1 = \frac{V_1}{R} \quad \text{and} \quad I_2 = \frac{V_2}{R} \] **Hint**: Use Ohm's Law to relate current to potential difference. 4. **Setting Up the Ratios**: - From the current expressions: \[ I_1 = n \cdot A \cdot e \cdot v_{d1} \quad \text{and} \quad I_2 = n \cdot A \cdot e \cdot v_{d2} \] - Therefore, we can write: \[ n \cdot A \cdot e \cdot v_{d1} = \frac{V_1}{R} \quad \text{and} \quad n \cdot A \cdot e \cdot v_{d2} = \frac{V_2}{R} \] **Hint**: Relate the drift velocities to the currents. 5. **Finding the Ratio of Drift Velocities**: - Dividing the two equations gives: \[ \frac{n \cdot A \cdot e \cdot v_{d1}}{n \cdot A \cdot e \cdot v_{d2}} = \frac{V_1}{V_2} \] - This simplifies to: \[ \frac{v_{d1}}{v_{d2}} = \frac{V_1}{V_2} \] - Substituting the values of \( V_1 \) and \( V_2 \): \[ \frac{v_{d1}}{v_{d2}} = \frac{1}{2} \] **Hint**: Use the relationship established to find the ratio of drift velocities. 6. **Conclusion**: - Therefore, the ratio of their drift velocities is: \[ \frac{v_{d1}}{v_{d2}} = \frac{1}{2} \] ### Final Answer: The ratio of the drift velocities \( v_{d1} : v_{d2} = 1 : 2 \).

To solve the problem, we need to find the ratio of the drift velocities of two identical conductors given that they have potential differences in the ratio of 1:2. ### Step-by-Step Solution: 1. **Understanding the Given Information**: - We have two identical conductors maintained at the same temperature. - The potential differences across them are in the ratio \( V_1 : V_2 = 1 : 2 \). - This implies that \( V_1 = k \) and \( V_2 = 2k \) for some constant \( k \). ...
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