When a current I is passed through a wire of constant resistance, it produces a potential difference V across its ends. The graph drawn between log I and log V will be

Options

A.
B.
C.
D.

Answer

A

Explanation

Since, `V = IR rArr log_(e) I + log_(e)R`
`= log_(e) I = log_(e)V - logR_(e)`
On compare with `Y = mX + C` we get `-ve` intercept
i.e. `- logR_(e)`