A wire is bent in the form of circle of radius 2m. Resistance per unit length of wire is `1//pi Omega//m`. Battery of 6V is connected between A & B. `angleAOB = 90^(@)`. Find the current through the battery-

Options

A. `8 A`
B. `4 A`
C. `3 A`
D. `9 A`

Answer

A

Explanation

`R_(1) = 1/pi xx (2pir)/4 =1 Omega, R_(2) = 1/pi xx (2pi r xx 3)/4 = 3 Omega`
`R_(eq) = (R_(1)R_(2))/(R_(1) + R_(2)) =(1 xx 3)/4 = 3/4 Omega`
`I = 6/3 xx 4 = 8A`