Home
Class 12
PHYSICS
In a typical Wheatstone network, the res...

In a typical Wheatstone network, the resistances in cyclic order are `A = 10 Omega, B = 5 Omega, C = 4 Omega` `D = 4 Omega` for the bridge to be balanced

A

`10 Omega` should be connected in parallel with A

B

`10 Omega` should be connected in series with A

C

`5 Omega` should be connected in series with B

D

`5 Omega` should be connected in parallel with B

Text Solution

Verified by Experts

The correct Answer is:
A

`A/B = D/C rArr 10/5 ne 4/4`
`rArr A^(.)/B = D/C rArr A^(.)/5 =4/4 = A^(.) = 5 Omega`
`10 Omega` resistance should be connected in parallel with A resistance.
Promotional Banner

Topper's Solved these Questions

  • CURRENT ELECTRICITY

    ERRORLESS|Exercise NCERT BASED QUESTIONS (KIRCHHOFF.S LAW, CELLS)|53 Videos
  • CURRENT ELECTRICITY

    ERRORLESS|Exercise NCERT BASED QUESTIONS (DIFFERENT MEASURING INSTRUMENTS) |74 Videos
  • CURRENT ELECTRICITY

    ERRORLESS|Exercise ASSERTION AND REASON|26 Videos
  • ATOMIC AND NUCLEAR PHYSICS

    ERRORLESS|Exercise Assertion and Reason|23 Videos
  • ELECTROMAGNETIC INDUCTION

    ERRORLESS|Exercise ASSERTION & REASON|20 Videos

Similar Questions

Explore conceptually related problems

In a typical wheatstone network the resistance in cyclic order are A= 10Omega,B=5O,ega,C=4Omega and D=4Omega for the bridge to be balanced.

In a typical Wheatstone's network, the resistances in the cyclic order are P=10 Omega, Q=5 Omega, S=4 Omega and R=4 Omega . For balancing the bridge, a resistance of

A Wheatstone network consists of four resistances (in cyclic order) 10Omega,5Omega,6Omega,6Omega . The resistance that must be connected across the 10Omega resistance so that the network becomes balanced is (in Ohm):

In Wheatstone bridge, the resistances in four arms are 10Omega,10Omega,10Omega and 20Omega . To make the bridge balance, resistance connected across 20Omega is

In the Wheatstone bridge network ABCD is balanced when P = 500 Omega, Q = 250 Omega and S = 12 Omega , what is the value of R ?

Four resistance A = 20 Omega , B = 30 Omega , C = 40 Omega, D = 60 Omega are connected arrange the heats produced per second in them in decreasing order

In the Wheatstone's bridge shown, P = 2 Omega, Q = 3 Omega, R = 6 Omega and S = 8 Omega . In order to obtain balance, shunt resistance across S must be

Four resistances arranged to form a Wheatstone network are 8Omega, 12Omega,6Omega and 27Omega resistance, so that the bridge is balanced, is

ERRORLESS-CURRENT ELECTRICITY-NCERT BASED QUESTIONS (Grouping of Resistances)
  1. In the arrangement of resistances shown below, the effective resistanc...

    Text Solution

    |

  2. In the circuit shown below the resistance of the galvanometer is 60Ome...

    Text Solution

    |

  3. In a typical Wheatstone network, the resistances in cyclic order are A...

    Text Solution

    |

  4. In the circuit shown in the figure, the current drawn from the battery...

    Text Solution

    |

  5. For the network shown in the figure the value of the current i is-

    Text Solution

    |

  6. For what value of unknown resistance X, the potential difference betwe...

    Text Solution

    |

  7. What current will flow through the 2 K Omega resistor in the circuit s...

    Text Solution

    |

  8. In this circuit, the value of I(2) is-

    Text Solution

    |

  9. In the electrical circuit shown in figure, the current through the 4 O...

    Text Solution

    |

  10. Nine resistors each of 1 kΩ are connected to a battery of 6 V as shown...

    Text Solution

    |

  11. A current of 2 A flows in a system of conductor as shown. The potentia...

    Text Solution

    |

  12. If the ammeter in the given circuit reads 2 A, the resistance R is-

    Text Solution

    |

  13. Resistors of 1, 2, 3 ohm are connected in the form of a triangle. If a...

    Text Solution

    |

  14. A parallel combination of two resistors, of 1 Omega each, is connected...

    Text Solution

    |

  15. In the circuit shown, the point B is earthed. The potential at the poi...

    Text Solution

    |

  16. The potential drop across the 3 Omega resistor is-

    Text Solution

    |

  17. A uniform wire of resistance 9 Omega is cut into 3 equal parts. They a...

    Text Solution

    |

  18. In the circuit shown below, the reading of the voltmeter V is-

    Text Solution

    |

  19. The current in a simple series circuit is 5.0 amp . When an additional...

    Text Solution

    |

  20. Figure showns a network of eight resistors numbered 1 to 8, each equal...

    Text Solution

    |