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For the network shown in the figure the ...

For the network shown in the figure the value of the current i is-

A

`(9V)/35`

B

`(5V)/18`

C

`(5V)/9`

D

`(18 V)/5`

Text Solution

Verified by Experts

The correct Answer is:
B
Balanced bridge,
`R_(eq) = (6 xx 9)/15 = 18/5 Omega`
`i = (V xx 5)/18 = (5V)/18`
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