In the electrical circuit shown in figure, the current through the `4 Omega` resistor is-

Options

A. `1 A`
B. 0.5 A
C. 0.25 A
D. 0.1 A

Answer

B

Explanation

`R_(eq) = 3 + 2 + (8 xx 8)/16 = 3 + 2 + 4 = 9 Omega`
`I = 9/9 = 1A`
`I_(4Omega) = 4/8 xx 1 = 0.5 A`