A uniform wire of resistance `9 Omega` is cut into 3 equal parts. They are connected in form of equilateral triangle `ABC`. A cell of e.m.f. `2V` and negligible internal resistance is connected across `B` and `C`. Potential difference across `AB` is

Options

A. 1 V
B. 2 V
C. 3 C
D. 0.5 V

Answer

A

Explanation

`R_(eq) = (6 xx 3)/9 = 2 Omega`
`I = 2/2 =1A`
`I_(AB) = 3/9 xx 1= 1/3 A`
`V_(AB) = 1/3 xx 3 = 1V`