In the given circuit diagram, in the steady state the current through the battery and the charge on the capacitor respectively are

Options

A. 1 A and `3 muC`
B. 17 A and `0 mu C`
C. `6/7 A` and `12/7 mu C`
D. 11 A and `3 muC`

Answer

D

Explanation

`I = 6/R_(eq) = 6 xx 11/6 = 11 A`
`1/R_(eq) = 1/1 + 1/2 + 1/3 = (6 + 3 +2)/6 = 11/6`
`R_(eq) =6/11 Omega`
Change on capacitor
`Q = CV = 0.5 xx 10^(-6) xx 6 = 3muC`