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n identical cells each of e.m.f. E and i...

n identical cells each of e.m.f. E and internal resistance r are connected in series. An external resistance R is connected in series to this combination. The current through R is

A

`(ne)/(R + nr)`

B

`("ne")/(nR +r)`

C

`E/(R + nr)`

D

`(ne)/(R + r)`

Text Solution

Verified by Experts

The correct Answer is:
A
`E_(eq) =ne`, Total resistance = nR + R
`I = (ne)/(nr + R)`
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