The internal resistances of two cells shown are `0.1Omega` and `0.3 Omega`. If `R = 0.2 Omega`, its potential difference across the cell

Options

A. B will zero
B. A will be zero
C. A and B will be 2V
D. A will be `gt 2V` and B will be `lt 2V`

Answer

A

Explanation

`I = 4/(0.2 + 0.1 + 0.3) = 4/0.6 = 20/3 A`
`V_(A) = 2-20/3 xx 0.1 = 2-2/3 = 4/3 V`
`V_(B) = 2 - 20/3 xx 0.3 = 2-2 = 0`