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A battery having e.m.f. 5 V and internal...

A battery having e.m.f. 5 V and internal resistance `0.5 Omega` is connected with a resistance of `4.5 Omega` then the voltage at the terminals of battery is

A

4.5 V

B

4 V

C

0 V

D

2 V

Text Solution

Verified by Experts

The correct Answer is:
A
`V = E-Ir = 5- (5/(4.5 + 0.5)) xx 0.5 rArr V = 4.5 `volt
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ERRORLESS-CURRENT ELECTRICITY-NCERT BASED QUESTIONS (KIRCHHOFF.S LAW, CELLS)
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  2. Two cells having e.m.f. 4 V, 2V and internal resistances 1 Omega, 1 Om...

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  3. A battery having e.m.f. 5 V and internal resistance 0.5 Omega is conne...

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  4. Two batteries A and B each of e.m.f. 2 V are connected in series to a...

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  5. When a resistor of 11 Omega is connected in series with an electric ce...

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  6. A capacitor is conneted to a cell emf E having some internal resistanc...

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  8. 5 cells, each of emf 0.2V and internal resistance 1 Omega are connecte...

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  9. In the circuit shown here, E(1) = E(2) = E(3) = 2 V and R(1) = R(2) = ...

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  10. Two batteries V(1) and V(2) are connected to three resistors as shown ...

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  11. Two cells having an internal resistance of 0.2 Omega and 0.4 Omega are...

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  12. The n rows each containing m cells in series are joined parallel. Maxi...

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  13. Two sources of equal emf are connected to an external resistance R. Th...

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  14. A battery of emf E has an internal resistance r. A variable resistacne...

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  15. v34

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  16. In the circuit shown in figure, reading of voltmeter is V1 when only S...

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  17. Twelve cells each having the same e.m.f are connected in series and...

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  18. Two cells, each of e.m.f. E and internal resistance r are connected in...

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  19. Consider four circuits shown in the figure below. In which circuit pow...

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  20. The emf of a battery is 2V and its internal resistance is 0.5Omega the...

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