Two cells A and B of e.m.f. 2V and 1.5V respectively, are connected as shown in figure through an external resistance `10Omega`. The internal resistance of each cell is `5Omega` The potential difference `E_A` and `E_B` across the terminals of the cells A and B respectively are

Options

A. `E_(A) = 2.0V, E_(B) = 1.5 V`
B. `E_(A) = 2.12 V, E_(B) = 1.375 V`
C. `E_(A) = 1.875 V,E_(B) =1.625 V`
D. `E_(A) = 1.875 V, E_(B) = 1.375 V`

Answer

C

Explanation

`I =(2-1.5)/20 = 1/40 A`
`E_(A) = 2-ir = 2-1/40 xx 5 = 1.875 V`
`E_(B) = 1.5 + ir =1.625 V`