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A galvanometer having a resistance of 8 ...

A galvanometer having a resistance of 8 ohm is shunted by a wire of resistance 2 ohm . If the total current is 1 amp , the part of it passing through the shunt will be

A

0.25 amp

B

0.8 amp

C

0.2 amp

D

0.5 amp

Text Solution

Verified by Experts

The correct Answer is:
B

`I_(s) = (8/(2 + 8))1 = 8/10 = 0.8 A`
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