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A 36 Omega galvanometer is shunted by re...

A `36 Omega` galvanometer is shunted by resistance of `4Omega`. The percentage of the total current, which passes through the galvanometer is

A

0.08

B

0.09

C

0.1

D

0.91

Text Solution

Verified by Experts

The correct Answer is:
C
`I_(g)R_(g) (1- I_(g))S`
`rArr I_(g) xx 36 = (I-I_(g)) xx 4`
`rArr 9 = I/I_(g) -1 rArr I/I_(g) = 10 rArr I_(g)/I = 1/10 = 10%`
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