In the circuit, shown the galvanometer G of resistance `60Omega` is shifted by a resistance r=0.02`Omega`. The current through R is nearly 1A. The value of resistance R (in ohm) is nearly.

Options

A. `1.00 Omega`
B. `5.00 Omega`
C. `11.0 Omega`
D. `60.00 Omega`

Answer

B

Explanation

`R_(eq) = (0.02 xx 60)/(60 + 0.02) = 0.02 Omega`
`I = 5/(R + R_(eq)) rArr 1 = 5/(R + 0.02)`
`rArr R = 5-0.02 = 4.98 Omega = 5 Omega`