Two bulbs `X` and `Y` having same voltage rating and of power 40 watt and 60 watt respectively are connected in series across a potential difference of 300 volt, then

Options

A. X will glow brighter
B. Resistance of Y is greater than X
C. Heat produced in Y will be greater than X
D. Voltage drop in X will be greater than Y

Answer

A

Explanation

`R_(x) =(300)^(2)/40 , R_(Y) = (300)^(2)/60`
Since, `R_(X) gt R_(Y)`