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Two bulbs are working in parallel order....

Two bulbs are working in parallel order. Bulb A is brighter than bulb B . If `R_(A)` and `R_(B)` are their resistance respectively then

A

`R_(A) gt R_(B)`

B

`R_(A) lt R_(B)`

C

`R_(A) = R_(B)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
In parallel `P prop 1/R`
Since, `P_(A) gt P_(B) rArr R_(A) lt R_(B)`
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