Two conductors made of the same material are connected across a common potential difference. Conductor A has twice the diameter and twice the length of conductor B . The power delivered to the two conductors `P_(A)` and `P_(B)` respectively is such that `P_(A)//P_(B)` equals to

Options

A. 0.5
B. 1
C. 1.5
D. 2

Answer

D

Explanation

`R_(A)/R_(B) = ((2l)/((pi(2r)^(2))/(l/(pir^(2))) =1/2 rArr 2R_(A) = R_(B)`
In parallel `P prop 1/R rArr P_(A)/P_(B) = R_(B)/R_(A) = 2:1`