Figure `7.37` shows a network of three resistances. When some potential difference is applied across the network , thermal powers dissipated by `A, B and C` are in the ratio

Options

A. `2:3:4`
B. `2:3:3`
C. `4:2:3`
D. `3:2:4`

Answer

C

Explanation

`P_(A) =((2l)/3)^(2) 3R = 4/3 i^(2)R`
`P_(B) = (i/3)^(2) 6R =2/3 i^(2)R`
`P_( C) = i^(2)R`
`P_(A): P_(B):_( C) = 4/3:2/3 :1 = 4:2:3`