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A 4mu F conductor is charged to 400 volt...

A `4mu F` conductor is charged to 400 volts and then its plates are joined through a resistance of `1k Omega` . The heat produced in the resistance is

A

0.16 J

B

1.28 J

C

0.64 J

D

0.32 J

Text Solution

Verified by Experts

The correct Answer is:
D
Heat produced = Energy stored in capacitor-
`=1/2 CV^(2) = 1/2 xx 4 xx 10^(-6) xx (400)^(2) = 0.32 J`
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