In the following circuit, `5Omega` resistor develops 45 J/s due to current flowing through it. The power developed across `12Omega` resistor is

Options

A. 16 W
B. 192 W
C. 36W
D. 64 W

Answer

B

Explanation

`i_(1)/i_(2) = 15/5 = 3/1`

Since,
`45 = i_(1)^(5)5 rArr i_(1) = 3A` and `i_(2) = 1 A`
`therefore I = i_(1) + i_(2) = 3 + 1 = 4A`
Power
`P_(12) = i^(2)R = (4)^(2) xx 12 =192 W`