A coil of wire of resistance `50 Omega` is embedded in a block of ice. If a potential difference of 210 V is applied across the coil, the amount of ice melted per second will be

Options

A. 4.12 g
B. 4.12 kg
C. 3.68 kg
D. 2.625 kg

Answer

D

Explanation

`Q/t =v^(2)/(4.2 R) = (mL)/t`
`m/t V = V^(2)/(4.2 RL) = (210)^(2)/(4.2 xx 50 xx 80) = 2.625 g`