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Three resistance P, Q, R each of 2 Omega...

Three resistance `P, Q, R` each of `2 Omega` and an unknown resistance `S` from the four amrs of a Wheatstone's bridge circuit. When a resistance of `6 Omega` is connected in parallel to `S` the bridge gets balanced. What is the value of `S` ?

A

`2 Omega`

B

`3 Omega`

C

`6 Omega`

D

`1 Omega`

Text Solution

Verified by Experts

The correct Answer is:
B
`(6 xx S)/(6 + S) = 2 rArr 6S = 2 xx 6 + 2s rArr S = 12/4 = 3 Omega`
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