Current through `3Omega` resistor is 0.8A, then potential drop through `4Omega` resistor is

Options

A. 9.6 V
B. 2.6 V
C. 4.8 V
D. 1.2 V

Answer

C

Explanation

`I_(3) = 0.8 A, I_(0) = 0.4 A`
`I_(T) = 1.2 A`
`V_(4) = 1.2 xx 4 = 4.8 V`