The resistance of 1 A ammeter is `0.018 Omega` . To convert it into 10 A ammeter, the shunt resistance required will be

Options

A. `0.18 Omega`
B. `0.0018 Omega`
C. `0.002 Omega`
D. `0.12 Omega`

Answer

C

Explanation

`S = (I_(g)/(I-I_(g))) xx R_(G) = (1 xx 0.018)/(10 -1) = 2 xx 10^(-3) = 0.002 Omega`