A milli voltmeter of 25 milli volt range is to be converted into an ammeter of 25 ampere range. The value (in ohm) of necessary shunt will be

Options

A. 0.001
B. 0.01
C. 1
D. `0.05`

Answer

B

Explanation

Since, `V_(G) = I_(g) R_(G) = 25 xx 10^(-3) V`
I = 25 A
`I_(g)R_(G) = (I-I_(g))S`
`rArr 25 xx 10^(3) = l xx S` (as `I gt gt I_(g)`)

`rArr S = (25 xx 10^(-3))/25 = 0.001 Omega`