Two electric bulbs, one of 200 volt 40 watt and the other 200 volt 100 watt are connected in a house wiring circuit

Options

A. They have equal currents through them
B. The resistance of the filaments in both the bulbs is same
C. The resistance of the filament in 40 watt bulb is more than the resistance in 100 watt bulb
D. The resistance of the filament in 100 watt bulb is more than the resistance in 40 watt bulb

Answer

C

Explanation

For 1st bulb, V = 200 volt and P = 40 watt
`R_(1) = V_(1)^(2)/P_(1) =(200)^(2)/40 = (4 xx 10^(40)/(4 xx 10)) =10^(3) Omega = 1000 Omega`
Similarly, for 2nd bulb: V = 200 volt and P = 100watt
`R_(2) = V_(2)^(2)/P_(2) = (200)^(2)/100 = (4 xx 10000)/100 = 400 Omega`