A wire connected in the left gap of a meter bridge balance a `10Omega` resistance in the right gap to a point, which divides the bridge wire in the ratio 3:2. If the length of the wire is 1m. The length of one ohm wire is

Options

A. `1.0 xx 10^(-2) m`
B. `1.0 xx 10^(-1) m`
C. `1.5 xx 10^(-1) m`
D. `1.5 xx 10^(-2) m`

Answer

B

Explanation

`R/10 = l_(1)/l_(2)`
`rArr R/10 = 3/2`
`R = 15 Omega`
Length of `15 Omega` resistance wire is 1.5 m
`therefore` Length of `1 Omega` resistance wire `=1.5/15 = 0.1`
`=1.0 xx 10^(-1) m`