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A light of wavelength 5890Å falls normal...

A light of wavelength `5890Å` falls normally on a thin air film. The minimum thickness of the film such that the film appears dark in reflected light is

A

`2.945 xx 10^(-7)`

B

`3.945 xx 10^(-7)`

C

`4.95 xx 10^(-7)`

D

`1.945 xx 10^(-7)`

Text Solution

Verified by Experts

The correct Answer is:
A

Thin film appears dark,
`2mut= nlambda implies t= (nlambda)/(2mu)`
`implies t_("min")= (lambda)/(2mu)= (5890 xx 10^(-10))/(2 xx 1)= 2.945 xx 10^(-7) m`
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