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In Young's double slit experiment, an in...

In Young's double slit experiment, an interference pattern is obtained on a screen by a light of wavelength `6000Å`, coming from the coherent sources `S_1` and `S_2`. At certain point P on the screen third dark fringe is formed. Then the path difference `S_1P-S_2P` in microns is

A

0.75

B

1.5

C

3

D

4.5

Text Solution

Verified by Experts

The correct Answer is:
B

For dark fringe
`S_(1)P-S_(2)P= ((2n-1)lambda)/(2)`
n= 3 and `lambda= 6000 A`
`S_(1)P-S_(2)P= ((2 xx 3-1) xx 6000 xx 10^(-10))/(2)= 1.5 xx 10^(-6) m = 1.5` micron
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ERRORLESS-WAVE OPTICS AND ELECTROMAGNETIC THEORY-NCERT BASED QUESTIONS (Young’s Double Slit Experiment and Biprism)
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  13. The maximum intensity of fringes in Young's experiment is I. If one of...

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  19. A thin sheet of glass (refractive index 1.5) of thickness 6 microns, i...

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