In Young's double slit experiment, distance between two sources is 0.1mm. The distance of screen from the sources is 20cm. Wavelength of light used is `5460 Å`. Then, angular position of first dark fringe is approximately

Options

A. `0.08^(@)`
B. `0.16^(@)`
C. `0.20^(@)`
D. `0.313^(@)`

Answer

D

Explanation

Angular position of `1^(st)` dark fringe
`theta= (lambda)/(d)= (5460 xx 10^(-10))/(0.1 xx 10^(-3))xx (180)/(pi)= 0.313^(@)`