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The intensity of the light coming from one of the slits in a Young's double slit experiment is double the intensity from the other slit. Find the ratio of the maximum intensity to the minimum intensity in the interference fringe pattern observed.

A

34

B

40

C

25

D

38

Text Solution

Verified by Experts

The correct Answer is:
A

`(I_("max"))/(I_("min"))= ((sqrt(I_(1))+ sqrt(I_(2)))^(2))/((sqrt(I_(1))+ sqrt(I_(2)))^(2))= [((sqrt(2)+1)I)/((sqrt(2)-1)I)]^(2)~~34`
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  16. A thin sheet of glass (refractive index 1.5) of thickness 6 microns, i...

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  20. In Young's double slit experiment, the aperture screen distance is 2m....

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