In Young's double slit experiment, the aperture screen distance is `2m`. The fringe width is `1mm`. Light of `600nm` is used. If a thin plate of glass `(mu=1.5)` of thickness `0.06mm` is placed over one of the slits, then there will be a lateral displacement of the fringes by

Options

A. 0 cm
B. 5 cm
C. 10 cm
D. 15 cm

Answer

B

Explanation

Lateral displacement of fringes
`=(beta)/(lambda) (mu-1)t= (1 xx 10^(-3))/(600 xx 10^(-9))(1.5-1) xx 0.06 xx 10^(-3)= 5cm`