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Light of wavelength 589.3nm is incident ...

Light of wavelength `589.3nm` is incident normally on the slit of width `0.1mm`. What will be the angular width of the central diffraction maximum at a distance of `1m` from the slit?

A

`.68^(@)`

B

`1.02^(@)`

C

`0.34^(@)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
Angular width of central maxima = `(2lambda)/(a)= (2 xx 589.3 xx 10^(-9))/(0.1 xx 10^(-3))"rad"= 0.68^(@)`
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