In a single-slit diffraction experiment, the width of the slit is made half of the original width:

Options

A. Reduce the distance between the slit and screen by half
B. Reduce the distance between the slit and the screen to `((1)/(4))^(th)` the original separation
C. Double the distance between the slit and the screen
D. No need to do anything, as the width of the central maxima does not depend on the slit width

Answer

A

Explanation

Width of central maxima= `(2lambdaD)/(a)` Now the width of the slit is reduced by half i.e. `a//2` then distance between the slit and screen reduce by half.