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An analyser is inclined to a polariser a...

An analyser is inclined to a polariser at an angle of `30^(0)` . The intensity of light emerging from the analyser is `(1)/(n)` th of that is incident on the polariser. Then n is equal to

A

`30^(@)`

B

`45^(@)`

C

`0^(@)`

D

`60^(@)`

Text Solution

Verified by Experts

The correct Answer is:
D
`I= I_(0)cos^(2)theta`
`implies (I_(0))/(8)= (I_(0))/(2) cos^(2)thetaimpliescostheta= (1)/(2) implies theta= 60^(@)`
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