A radio receiver antenna that is `2 m` long is oriented along the direction of the electromagnetic wave and receives a signal of intensity `5xx10^(-16) W//m^(2)`. The maximum instaneous potential difference across the two ends of the antenna is

Options

A. `1.23 muV`
B. `1.23m V`
C. `1.23 V`
D. `12.3 mV`

Answer

A

Explanation

Intensity = `(1)/(2)epsilon_(0)cE_(0)^(2)`
`E_(0)= sqrt((2I)/(epsilon_(0)c))= sqrt((2 xx 5 xx 10^(-16))/(8.85 xx 10^(-12) xx 3 xx 10^(8))) implies E_(0)= 0.6 1 xx 10^(-6)(V)/(m)`
`implies E_(0)= 0.61 xx 10^(-6) (V)/(m)`
`V= E_(0)d= 0.61 xx 10^(-6) xx 2= 1.23 muV`