A point source of electromagnetic radiation has an average power output of `1500W`. The maximum value of electric field at a distance `3m` from this source in `Vm^-1` is

Options

A. 500
B. 100
C. `(500)/(3)`
D. `(250)/(3)`

Answer

B

Explanation

`E= sqrt((P)/(2piR^(2)epsilon_(0)c)) [As I=(P)/(4piR^(2))= (1)/(2)epsilon_(0)E^(2)c]= sqrt((1500)/(2 xx 3.14 xx (3)^(2) xx 8.85 xx 10^(-12) xx 3 xx 10^(8)))= 100V//m`