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An electromagnetic wave of frequency v=3...

An electromagnetic wave of frequency `v=3.0 MHz` passes from vacuum into a dielectric medium with permittivity `epsilon=4.0`. Then

A

Wavelength is doubled and the frequency remains unchanged

B

Wavelength is doubled and frequency becomes half

C

Wavelength is halved and frequency remains unchanged

D

Wavelength and frequency both remain unchanged

Text Solution

Verified by Experts

The correct Answer is:
C
Refractive index= `sqrt((muepsilon)/(mu_(0)epsilon_(0)))= sqrt(4)= 2` [Let `mu= mu_(0)`]
Speed and wavelength of wave becomes half and frequency remains unchanged.
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