In a double slit experiment, the two slits are `1mm` apart and the screen is placed `1m` away. A monochromatic light of wavelength `500nm` is used. What will be the width of each slit for obtaining ten maxima of double slit within the central maxima of single-slit pattern?

Options

A. 0.1mm
B. 0.5mm
C. 0.02mm
D. 0.2mm

Answer

D

Explanation

d = 1mm, D = 1m , `lambda` = 500nm
Given, `(10lambdaD)/(d)= (2lambdaD)/(a)`
`implies a= (d)/(5)= (1)/(5) xx 10^(-3)= 0.2mm`