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In young's double slit experiment the se...

In young's double slit experiment the separation `d` between the slits is `2mm`, the wavelength `lambda` of the light used is `5896 Å` and distance `D` between the screen and slits is `100 cm`. It is found that the angular width of the fringes is `0.20^(@)`. To increases the fringe angular width to `0.21^(@)`(with same `lambda` and `D`) the separtion between the slits needs to be changed to

A

1.8 mm

B

1.9 mm

C

2.1 mm

D

1.7 mm

Text Solution

Verified by Experts

The correct Answer is:
B

`theta= (lambda)/(d), (theta_(1))/(theta_(2))= (d_(2))/(d_(1))`
`(0.2)/(0.21)=(d_(2))/(2) implies d_(2)= (0.2)/(0.21) xx 2= 1.9 mm`
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