For a parallel beam of monochromatic light of wavelength `'lambda'` differaction is produced by a single slit whose width `'a'` is of the order as wavelength of the light. If `'D'` is the distance of the screen from the slit, the width of the central maxima will be

Options

A. `(Dlambda)/(a)`
B. `(Dlambda)/(a)`
C. `(2Da)/(lambda)`
D. `(2Dlambda)/(a)`

Answer

D

Explanation

Angular width of central maxima = `(2lambda)/(a)`
Linear width of central maxima = `(2lambdaD)/(a)`